Creating an object for every property

When working with TypeScript, you may come across a scenario where you need to create an object for every property in a given object. This can be useful in situations where you want to perform operations on each property individually or pass them as separate arguments to a function. In this blog post, we will explore different solutions to achieve this.

Solution 1: Using a for…in loop

One way to create an object for every property is by using a for…in loop. This loop iterates over all enumerable properties of an object and allows you to perform actions on each property.

Here’s an example:


const myObject = {
  property1: 'value1',
  property2: 'value2',
  property3: 'value3'
};

const objectArray = [];

for (const property in myObject) {
  if (myObject.hasOwnProperty(property)) {
    const obj = {};
    obj[property] = myObject[property];
    objectArray.push(obj);
  }
}

console.log(objectArray);

The above code creates an empty array objectArray and then iterates over each property of myObject. For each property, it creates a new object with the property name as the key and the property value as the value. Finally, it pushes the object into the objectArray.

The output of the above code will be:


[
  { property1: 'value1' },
  { property2: 'value2' },
  { property3: 'value3' }
]

Solution 2: Using Object.entries()

Another approach to creating an object for every property is by using the Object.entries() method. This method returns an array of a given object’s own enumerable property [key, value] pairs.

Here’s an example:


const myObject = {
  property1: 'value1',
  property2: 'value2',
  property3: 'value3'
};

const objectArray = Object.entries(myObject).map(([key, value]) => ({ [key]: value }));

console.log(objectArray);

In the above code, we use Object.entries() to get an array of [key, value] pairs for each property in myObject. We then use Array.map() to create a new object for each pair, with the key as the property name and the value as the property value.

The output of the above code will be the same as in Solution 1:


[
  { property1: 'value1' },
  { property2: 'value2' },
  { property3: 'value3' }
]

These are two different solutions to create an object for every property in TypeScript. Depending on your specific use case, you can choose the one that suits your needs best.

We hope this blog post has been helpful in solving your problem. If you have any further questions, feel free to reach out to us. Happy coding!

Creating an object for every property