How to get each key of an object differently then push it into a new object?
When working with TypeScript, there may be situations where you need to extract each key of an object and push it into a new object. In this blog post, we will explore different solutions to achieve this.
Solution 1: Using a for…in loop
One way to accomplish this is by using a for...in
loop to iterate over the keys of the object and push them into a new object.
const originalObject = {
key1: 'value1',
key2: 'value2',
key3: 'value3'
};
const newObject = {};
for (let key in originalObject) {
newObject[key] = originalObject[key];
}
The above code snippet creates a new object newObject
and iterates over each key in the originalObject
using the for...in
loop. It then assigns each key-value pair to the new object.
Solution 2: Using Object.keys() and Array.reduce()
Another approach is to use the Object.keys()
method to get an array of the keys of the object, and then use the reduce()
method to create a new object.
const originalObject = {
key1: 'value1',
key2: 'value2',
key3: 'value3'
};
const newObject = Object.keys(originalObject).reduce((obj, key) => {
obj[key] = originalObject[key];
return obj;
}, {});
In the above code snippet, Object.keys()
returns an array of keys from the originalObject
. The reduce()
method then iterates over each key and assigns the corresponding value to the new object newObject
.
Solution 3: Using Object.assign()
An alternative solution is to use the Object.assign()
method to copy the keys and values from the original object to a new object.
const originalObject = {
key1: 'value1',
key2: 'value2',
key3: 'value3'
};
const newObject = Object.assign({}, originalObject);
The above code snippet creates a new object newObject
using Object.assign()
and assigns the keys and values from the originalObject
to the new object.
Conclusion
In this blog post, we explored three different solutions to extract each key of an object and push it into a new object in TypeScript. Whether you choose to use a for...in
loop, Object.keys()
with reduce()
, or Object.assign()
, you now have multiple options to achieve the desired result. Choose the solution that best fits your needs and coding style.
Remember to consider the specific requirements of your project and the performance implications of each solution before making a decision.
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