I face some UI glitch issue because the Boolean value get from state and frequently updated

I face some UI glitch issue because the Boolean value get from state and frequently updated

When working with TypeScript, it is common to encounter UI glitch issues when using boolean values from state that are frequently updated. This can happen due to the asynchronous nature of state updates and rendering in React. However, there are a few solutions to mitigate these glitches and ensure a smooth user experience.

Solution 1: Use a useEffect hook with a dependency array

One way to address this issue is by using the useEffect hook with a dependency array. By specifying the boolean value as a dependency, the effect will only be triggered when the value changes. This ensures that the UI updates synchronously with the state changes.


import React, { useEffect, useState } from 'react';

const MyComponent = () => {
  const [isBooleanValue, setIsBooleanValue] = useState(false);

  useEffect(() => {
    // Your logic here
    // This effect will be triggered whenever isBooleanValue changes
  }, [isBooleanValue]);

  return (
    // Your JSX here
  );
};

Solution 2: Use a CSS transition or animation

If the UI glitch is related to a visual transition or animation, you can use CSS transitions or animations to smoothen the effect. By applying a transition or animation to the relevant CSS properties, you can create a smooth visual change when the boolean value updates.


import React, { useState } from 'react';

const MyComponent = () => {
  const [isBooleanValue, setIsBooleanValue] = useState(false);

  const handleButtonClick = () => {
    setIsBooleanValue(!isBooleanValue);
  };

  return (
    
); };

In the above example, we toggle the boolean value when the button is clicked. The CSS class “active” is added to the component when the boolean value is true, triggering the transition or animation defined in your CSS.

Solution 3: Use a debounce function

If the UI glitch is caused by frequent updates to the boolean value, you can use a debounce function to delay the state update and ensure that the UI only reflects the final value after a certain period of inactivity.


import React, { useState } from 'react';

const debounce = (func, delay) => {
  let timeoutId;
  return (...args) => {
    clearTimeout(timeoutId);
    timeoutId = setTimeout(() => {
      func.apply(null, args);
    }, delay);
  };
};

const MyComponent = () => {
  const [isBooleanValue, setIsBooleanValue] = useState(false);

  const handleBooleanValueChange = debounce((value) => {
    setIsBooleanValue(value);
  }, 300);

  const handleChange = (event) => {
    const { checked } = event.target;
    handleBooleanValueChange(checked);
  };

  return (
    
); };

In the above example, we debounce the state update using a debounce function. This ensures that the state is only updated after a 300ms delay, reducing the frequency of UI updates and potential glitches.

By implementing one of these solutions, you can effectively address UI glitch issues caused by frequently updated boolean values from state in TypeScript. Choose the solution that best fits your specific use case and enjoy a smoother user experience.


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