Switch statements are a powerful tool in JavaScript that allow you to execute different blocks of code based on different conditions. However, what if you need to execute the same code for multiple cases? In this blog post, we will explore different ways to handle multiple cases in a switch statement in JavaScript.
Method 1: Repeating the same code
One straightforward way to handle multiple cases in a switch statement is to repeat the same code for each case. Although this method works, it can be repetitive and lead to code duplication. Here’s an example:
switch (fruit) {
case 'apple':
// code for apple
break;
case 'banana':
// code for banana
break;
case 'orange':
// code for orange
break;
case 'mango':
// code for mango
break;
case 'kiwi':
// code for kiwi
break;
// Repeat the same code for each case
case 'grape':
// code for grape
break;
case 'watermelon':
// code for watermelon
break;
case 'pineapple':
// code for pineapple
break;
// ...
}
Method 2: Grouping cases
To avoid code duplication, you can group multiple cases together and execute the same code for each group. This approach can make your code more concise and easier to maintain. Here’s an example:
switch (fruit) {
case 'apple':
case 'banana':
case 'orange':
case 'mango':
case 'kiwi':
// code for all these fruits
break;
case 'grape':
case 'watermelon':
case 'pineapple':
// code for all these fruits
break;
// ...
}
Method 3: Using an array of cases
Another way to handle multiple cases in a switch statement is by using an array of cases. This approach allows you to define the cases in an array and loop through them to execute the code. Here’s an example:
const fruits = ['apple', 'banana', 'orange', 'mango', 'kiwi'];
for (const fruit of fruits) {
switch (fruit) {
case 'apple':
case 'banana':
case 'orange':
case 'mango':
case 'kiwi':
// code for all these fruits
break;
// ...
}
}
These are three different ways to handle multiple cases in a switch statement in JavaScript. Choose the method that best fits your code structure and requirements. Happy coding!
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